16x^2+9x=7

Solution for 16x^2+9x=7 equation:

16x^2+9x=7

We move all terms to the left:

16x^2+9x-(7)=0

a = 16; b = 9; c = -7;
Δ = b2-4ac
Δ = 92-4·16·(-7)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-23}{2*16}=\frac{-32}{32}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+23}{2*16}=\frac{14}{32}
=7/16
$